Privacy Policy
Home » Problems » bvpT19

bvpT19

 

 

bvpT19
Contributor:  testset of J.R. Cash
Discipline:  academic test
Accession:  2013

 

 

 

Short description:

A second order differential equations that is reduced to a first order system of 2 equations.

Applicable solvers:

all the solvers supported by the Test Set.

 

Plots of the solution <- click to generate the plots of the solution and the textual output

 

Mathematical description:

 

 

The problem is

    \begin{eqnarray*} 	\lambda z'' = -\exp(z) z' + \frac{\displaystyle{\pi}}{\displaystyle{2}} \sin(\pi t / 2) \exp(2z), \;\;\;z(0) = 0, \;\;\; z(1) =0 	\end{eqnarray*}

with

    \[ 	z \in \mathbb{R} , \;\;\; t\in [0,1]. 	\]

We write this problem in first order form by defining y_1=z and y_2=z', yielding a system of differential equations of the form

    \begin{equation*} 	\left(\begin{array}{c} 	y_1\\ 	y_2 	\end{array}\right)'= 	\left(\begin{array}{c} 	y_2\\ 	\frac{1}{\lambda}f(t,y_1,y_2) 	\end{array}\right), 	\end{equation*}

where

    \begin{equation*} 	f(t,z,z') = -\exp(z) z' + \frac{\displaystyle{\pi}}{\displaystyle{2}} \sin(\pi t / 2) \exp(2z), 	\end{equation*}

with

    \[ 	(y_1,y_2)^T \in \mathbb{R}^{2} , \;\;\; t \in [0,1]. 	\]

The boundary conditions are obtained from

    \begin{equation*} 	\left( 	\begin{array}{cc} 	1 & 0 \\ 	0 & 0 \\ 	\end{array} 	\right) 	\left(\begin{array}{c} 	y_{1}(0)\\ 	y_{2}(0) 	\end{array}\right) 	+ 	\left( 	\begin{array}{cc} 	0 & 0 \\ 	1 & 0 \\ 	\end{array} 	\right) 	\left(\begin{array}{c} 	y_{1}(1)\\ 	y_{2}(1) 	\end{array}\right)=\left(\begin{array}{c} 	0\\ 	0 	\end{array}\right). 	\end{equation*}

 
 

Download: